Решите плиз задания.или обьясните как решать

Решите задачу:

$5) 1) \frac1{11^{11}} = 11^{-11}; 2) \frac1{k^4} = k^{-4}; 3) \frac{x^2}y = x^2y^{-1} 4) \frac{m^6}{n^6} = m^6n^{-6}; \\5) \frac{(2x-y)^3}{(x-2y)^9} = (2x-y)^3(x-2y)^{-9}$

$6) 1) 1 = 2^0 = \frac12^0; 2) 2 = 2^1 = \frac12^{-1}; 3) 4 = 2^2 = \frac12^{-2}; 4) 8 = 2^3 = \frac12^{-3}; 5) 16 = 2^4 = \frac12^{-4}; 6) 32 = 2^5 = \frac12^{-5}; 7) 64 = 2^6 = \frac12^{-6}\\8)\frac12 = 2^{-1} = \frac12^1; 9) \frac14 = 2^{-2} = \frac12^2; 10) \frac18 = 2^{-3} = \frac12^3; 11) \frac1{16} = 2^{-4} = \frac12^4; 12) \frac1{32} = 2^{-5} = \frac12^5; 13) \frac1{64} = 2^{-6} = \frac12^6$