A. 3^x ≤ 3^1
x≤1
Б. (3)^(-x) ≤ 3^1
-x≤1
x≥-1
В. 3^(-x)≥3^1
-x≥1
x≤-1
Г. 3^x ≥3^1
x≥1
упрощение:
(x+3)^2/(x^2 +x-6) * (x^2 - 4)/(3x +9) = ((x+3)*(x+2)*(x-2))/((x^2 + x - 6)*3*(x +3)) =
((x+2)*(x-2))/((x^2 + x - 6)*3) = ((x+2)*(x-2))/(3*(x-2)*(x+3)) = (x+2)/(3*(x+3))