Помогите решить по математике

$\frac{x}{x + 2} - \frac{(x - 2) {}^{2} }{2} ( \frac{1}{x {}^{2} - 4 } + \frac{1}{x {}^{2} - 4x + 4 } ) =0 \\ \\ 1) \: \frac{1}{(x - 2)(x + 2)} + \frac{1}{(x - 2)(x - 2)} = \frac{x - 2 + x + 2}{(x - 2)(x - 2)(x + 2)} = \frac{2x}{(x - 2) {}^{2}(x + 2) } \\ \\ 2) \: \frac{(x - 2)(x - 2)}{2} \times \frac{2x}{(x - 2)( x - 2)(x + 2)} = \frac{x}{x + 2} \\ \\ 3) \: \frac{x}{ x+ 2} - \frac{x}{x + 2} = 0$

ч.т.д.