Помогите3 вариант9 класс

1.
$14 \times 8 {}^{ \frac{1}{3} } = 14 \times (2 {}^{3} ) {}^{ {}^{ \frac{1}{3} } } = 14 \times 2 = 28$
$32 {}^{ - \frac{1}{5} } = (2 {}^{5} ) {}^{ \frac{1}{5} } = 2$
2.
$x {}^{ \frac{1}{2} } \times x {}^{ - \frac{1}{6} } = x {}^{ - \frac{1}{3} } = \frac{1}{x {}^{ \frac{1}{3} } } = \frac{1}{ \sqrt[3]{x} }$
$\frac{ a \times a {}^{ - \frac{3}{8} } }{a {}^{ \frac{1}{4} } } = a {}^{ \frac{5}{4} } \times a {}^{ - \frac{1}{4} } = a$
$( {b}^{ \frac{1}{8} } ) {}^{8} \times b {}^{ - \frac{1}{3} } = b \times b {}^{ - \frac{1}{3} } = b {}^{\frac{2}{3} }$
3.
$\sqrt[3]{a {}^{5} } \times a {}^{ - \frac{1}{6} } = a {}^{ \frac{5}{3} } \times a {}^{ - \frac{1}{6} } = a {}^{1.5}$
4.
$\frac{a + 3a {}^{ \frac{1}{2} } }{a {}^{ \frac{1}{2} } + 3} = \frac{a {}^{ \frac{1}{2} } (a { }^{ \frac{1}{2} } + 3)}{a {}^{ \frac{1}{2} } + 3 } = a {}^{1.5}$

$\frac{x - 36}{ x^{ \frac{1}{2} } - 6} = \frac{(x { {}^{ \frac{1}{2} } } - 6)(x {}^{ \frac{1}{2} } + 6)}{ {x}^{ \frac{1}{2} } - 6} = {x}^{ \frac{1}{2} } + 6$