Помогите решить все пожалуйст заранее спасибо

Question

Дан 1 ответ

ElectroM17_zn · Answer 1 · 2020-05-21T19:19:11+0000

1) $(\frac{6}{5} - \frac{3}{4}) * \frac{2}{3}$ = $\frac{24}{20} - \frac{15}{20} = \frac{9}{20}$ => $\frac{9}{20} * \frac{2}{3} = \frac{2}{3}$

НОЗ в скобках: 20.

2) $(\frac{6}{5} - \frac{2}{3}) * \frac{1}{2}$ = $\frac{18}{15} - \frac{10}{15} = \frac{8}{15}$ => $\frac{8}{15} * \frac{1}{2} = \frac{4}{15}$

НОЗ в скобках: 15.

3) $(\frac{11}{18} - \frac{4}{9} * \frac{3}{16}$ = $\frac{4}{9} * \frac{3}{16} = 12$

$\frac{11}{18} - 12 = \frac{11}{18} - 11\frac{18}{18}$ = $-11\frac{7}{18}$

4) $\frac{29}{30} - \frac{5}{18} * \frac{6}{25} = \frac{5}{18} * \frac{6}{25} = 15\\\\\frac{29}{30} - 15 = \frac{29}{30} - 14\frac{30}{30} = -14\frac{1}{30}$

5) \frac{8}{5} * \frac{17}{8} = \frac{17}{5} = 3\frac{2}{5} = \frac{17}{5}" alt="\frac{8}{5} * (\frac{3}{4} + \frac{11}{8}) = \frac{6}{8} + \frac{11}{8} = \frac{17}{8} => \frac{8}{5} * \frac{17}{8} = \frac{17}{5} = 3\frac{2}{5} = \frac{17}{5}" align="absmiddle" class="latex-formula">

НОЗ в скобках: 8.

6) \frac{18}{7} * \frac{23}{18} = \frac{23}{7} = 3\frac{2}{7}" alt="\frac{18}{7} * (\frac{4}{9} + \frac{15}{18}) = (\frac{8}{18} + \frac{15}{18}) = \frac{23}{18} => \frac{18}{7} * \frac{23}{18} = \frac{23}{7} = 3\frac{2}{7}" align="absmiddle" class="latex-formula">

НОЗ в скобках: 18.

7) $\frac{8}{5} * \frac{3}{4} + \frac{11}{8} = \frac{6}{5} + \frac{11}{8} = \frac{48}{40} + \frac{55}{40} = \frac{103}{40} = 2\frac{23}{40}$

НОЗ в скобках: 40.

8) $\frac{18}{7} * \frac{4}{9} + \frac{15}{14} = \frac{8}{7} + \frac{15}{14} = \frac{16}{14} + \frac{15}{14} = \frac{31}{14} = 2\frac{3}{14}$

НОЗ в скобках: 14.

10) $72 * (\frac{19}{24} - \frac{7}{12} + \frac{3}{8}) = 72 * \frac{14}{24} = \frac{72}{1} * \frac{14}{24} = 42 \\\frac{19}{24} - \frac{7}{12} = \frac{19}{24} - \frac{14}{24} = \frac{5}{24} \\\\\frac{5}{24} + \frac{3}{8} = \frac{5}{24} + \frac{9}{24} = \frac{14}{24}$

НОЗ 1) = 24, НОЗ 2) = 24.