Решите пожалуйста a1 и b1

$\frac{ {y}^{ - 16} }{ {( {y}^ { - 3}) }^{4} } = \frac{ {y}^{ - 16} }{ {y}^{ - 12} } = {y}^{ - 4}$
у=1/2
значит, у(-⁴)=2⁴=16
$\frac{ {5}^{ - 4} \times {5}^{ - 9} }{ {5}^{ - 12} } = \frac{ {5}^{ - 13} }{ {5}^{ - 12} } = {5}^{ - 1}$
=1/5
${10}^{ - 1} = \frac{1}{10} \\ {10}^{ - 2} = \frac{1}{100}$
с этого:
$\frac{3.2}{10} \times \frac{2}{100} = \frac{6.4}{1000} = 0.0064$
${( {a}^{2} )}^{ - 3} = {a}^{ - 6}$
$\frac{ {a}^{ - 9} }{ {a}^{ - 6} } = {a}^{ - 3}$
$\frac{1}{ {x}^{ - 1} } = \frac{1}{ \frac{1}{x} } = x$
$\frac{1}{ {x}^{ - 2} } = \frac{1}{ \frac{1}{ {x}^{2} } } = {x}^{2}$
$\frac{x}{ {x}^{2} } = \frac{1}{x} = \frac{1}{ - 2} = - 0.5$