ОДЗ: x>0 log²₃x - 2(log₃3+log₃x) - 1 =0 log₃x = t t² - 2(1+t) - 1=0 t² - 2 - 2t - 1=0 t² - 2t - 3=0 t₁ = -1 t₂ = 3 log₃x = -1 x = 1/3 log₃x = 3 x = 27 Ответ: 1/3: 27