3 cos 3600°+sin(-1560°)+cos(-450°)=

Question

3 cos 3600°+sin(-1560°)+cos(-450°)=

Answer 1

3Cos3600° + Sin(- 1560°) + Cos( - 450°) = 3Cos(360° * 10 + 0°) -

- Sin(360° * 4 + 120°) + Cos(360° + 90°) = 3Cos0° - Sin120° + Cos90° =

= 3 * 1 - √3/2 +0 = 3 - √3/2