дано
m(CxHyOzNq) = 10.5 g
m(H2O) = 6.3 g
V(CO2) = 6.72 L
V(N2) = 1.12 L
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CxHyOzNq-?
n(H) = 2n(H2O) = 2n(m/M) = 2(6.3 / 18) = 0.7 mol
M(H) = 1 g/mol
m(H) = n*M = 0.7 * 1 = 0.7 g
n(C) = n(CO2) = v(CO2) / Vm = 6.72 / 22.4 = 0.3 mol
M(C) = 12 g/mol
m(C) = n*M = 0.3*12 = 3.6 g
n(N) = 2n(V(N2) / Vm) = 2(1.12 / 22.4) = 0.1 mol
M(N) = 14g/mol
m(N) = n*M = 0.1*14 = 1.4 g
m(O) = m(CxHyOzNq) - (m(C)+m(H)+m(N)) = 10.5-(0.7+3.6+1.4) = 4.8 g
M(O) = 16 g/mol
n(O) = m/M = 4.8 / 16 = 0.3 mol
C : H : N : O = 0.3 : 0.7 : 0.1 : 0.3 = 3 : 7 : 1: 3
C3H7NO3 - изопропилнитрат
ответ C3H7O3N
5)
дано
m(CxHyNz) = 4.65 g
m(H2O) = 3.15 g
V(CO2) = 6.72 L
V(N2) = 0.56 L
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CxHyNz-?
n(H) = 2n(H2O) = 2*3.15 / 18 = 0.35 mol
n(C) = n(CO2) = V(CO2) / Vm = 6.72 / 22.4 = 0.3 mol
n(N) =2n(V(N2) / Vm) = 2*0.56 / 22.4 = 0.05 mol
C : H : N = 0.3 : 0.35 : 0.05 = 6 :7 : 1
C6H7N - анилин
ответ C6H7N