(x+1)²-2 (x+1)(y+1)+(y+1)² если х=95, у=85 3х²-6ху+3у² если х=65, у=15

Question

(x+1)²-2 (x+1)(y+1)+(y+1)² если х=95, у=85 3х²-6ху+3у² если х=65, у=15

Comments

(x+1)²-2*(x+1)*(y+1)+(y+1)² = (x+1-y-1)² = (x-y)² = (95-85)² = 10² = 100

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3*х²-6*х*у+3*у² = 3*(х²-2*x*у+у²) = 3*(x-y)² = 3*(65-15)² = 3*50² = 3*2500=7500

Answer 1

Ответ на первое и на второе

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