t^2-7t+10=0\\D=9\\t={2;5}=>2x^2+3x=2\\2x^2+3x-2=0\\D=25\\x={-2;\frac{1}{2} }\\2x^2+3x=5<=>2x^2+3x-5=0\\a+b+c=0=>x={-\frac{5}{2} ;1}\\x={-\frac{5}{2} ;-2;\frac{1}{2} ;1}\\" alt="(2x^2+3x-1)^2-10x^2-15x+9=0\\2x^2+3x=t=>t^2-7t+10=0\\D=9\\t={2;5}=>2x^2+3x=2\\2x^2+3x-2=0\\D=25\\x={-2;\frac{1}{2} }\\2x^2+3x=5<=>2x^2+3x-5=0\\a+b+c=0=>x={-\frac{5}{2} ;1}\\x={-\frac{5}{2} ;-2;\frac{1}{2} ;1}\\" align="absmiddle" class="latex-formula">
\frac{t^2+2t-3}{t} =0\\t\neq0\\t^2+2t-3=0\\a+b+c=0=>t={-3;1}=>\frac{x^2+2x-6}{x} =-3<=>\frac{x^2+5x-6}{x} =0\\x^2+5x-6=0\\a+b+c=0=>x={-6;1}\\\frac{x^2+2x-6}{x}=1<=>\frac{x^2+x-6}{x}=0\\x^2+x-6=0\\D=25\\x={-3;2} \\x\neq0\\x^2+2x-6\neq 0\\x={-6;-3;1;2}" alt="\frac{x^2+2x-6}{x}-\frac{3x}{x^2+2x-6}=-2\\\frac{x^2+2x-6}{x}=t=>\frac{t^2+2t-3}{t} =0\\t\neq0\\t^2+2t-3=0\\a+b+c=0=>t={-3;1}=>\frac{x^2+2x-6}{x} =-3<=>\frac{x^2+5x-6}{x} =0\\x^2+5x-6=0\\a+b+c=0=>x={-6;1}\\\frac{x^2+2x-6}{x}=1<=>\frac{x^2+x-6}{x}=0\\x^2+x-6=0\\D=25\\x={-3;2} \\x\neq0\\x^2+2x-6\neq 0\\x={-6;-3;1;2}" align="absmiddle" class="latex-formula">