2x + 2 [(5-x) + 2x] = 2 (5 + 2x)
2x + 2 [(5-x) + 2x] = 2 (5 + 2x) = 2x + 2 [5-x + 2x] = 2 (5 + 2x) = 2x + 2 [x + 5] = 10 + 4x = 2x + 2x + 10 = 10 + 4x = 4x + 10 = 10 + 4x => 0 = 0
В приложении...........................