Помогите решить, пожалуйста. СРОЧНО!

1. 4xy-2y+9xy+6x=13xy6x-2y

2. x^{2}(x-1)=10=>1. x^{2}=10=>x=\sqrt{10} .2. x-1=10=>x=11.=>x1=\sqrt{10} =>x2=11" alt="(2x^{3} -x^{2} -3x+7)-(x^{3} -3x+17)=2x^{3} -x^{2} -3x+7-x^{3}+3x-17=x^{3} -x^{2}-10=>x^{2}(x-1)=10=>1. x^{2}=10=>x=\sqrt{10} .2. x-1=10=>x=11.=>x1=\sqrt{10} =>x2=11" align="absmiddle" class="latex-formula">

3. x^{2}-3x-x+3=x^{2} =>-4x+3=0=>-4x=-3=>x=\frac{3}{4}=>x=0,75" alt="(x-1)*(x-3)=x^{2} => x^{2}-3x-x+3=x^{2} =>-4x+3=0=>-4x=-3=>x=\frac{3}{4}=>x=0,75" align="absmiddle" class="latex-formula">

4. $-4^{3} +(-0,3)^{3}*2^{2} = -2^{6}-0,3^{3} *2^{2}=(-16-(\frac{3}{10})^{3})*4=-\frac{16027}{1000} *4=-64\frac{27}{250} =64,108$

5.2(x+8)-3(x-2)=12=>2x+16-3x+6=12=>-x+22=12=>-x=-10=>x=10" alt="\frac{x+8}{3} -\frac{x-2}{2}=2=>2(x+8)-3(x-2)=12=>2x+16-3x+6=12=>-x+22=12=>-x=-10=>x=10" align="absmiddle" class="latex-formula">