dx=-\frac{dt}{3}\\t_1=10-3*3=1\\t_2=10-3*\frac{1}{3}=9" alt="\displaystyle\int\limits^3_\frac{1}{3}\frac{dx}{\sqrt{10-3x}}=\frac{1}{3}\int\limits^9_1\frac{dt}{\sqrt{t}}=\frac{2\sqrt{t}}{3}|^9_1=2-\frac{2}{3}=1\frac{1}{3}\\t=10-3x;dt=-3dx=>dx=-\frac{dt}{3}\\t_1=10-3*3=1\\t_2=10-3*\frac{1}{3}=9" align="absmiddle" class="latex-formula">