3^{2x} *3^{3x+6} \geq 3^{1}=> 3^{5x+6} \geq 3^{1} =>5x+6\geq 1=>5x\geq 1-6=>5x\geq -5=>x\geq -1." alt="9^{x} * 27^{x+2}\geq 3=>3^{2x} *3^{3x+6} \geq 3^{1}=> 3^{5x+6} \geq 3^{1} =>5x+6\geq 1=>5x\geq 1-6=>5x\geq -5=>x\geq -1." align="absmiddle" class="latex-formula">
Ответ: x∈[-1,+∞).