1)
дано
V(CO2) = 448 L
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m(C2H6)-?
2C2H6+7O2-->4CO2+6H2O
n(CO2) = V(CO2) / Vm = 448 / 22.4 = 20 mol
2nC2H6 = 4nCO2
n(C2H6) = 2*20 / 4 = 10 mol
M(C2H6) =30 g/mol
m(C2H6) = n*M = 10*30 = 300 g
ответ 300 г
2)
дано
V(O2) = 112 L
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m(C3H8)-?
C3Н8+5O2-->3CO2+4H2O
n(O2) = V(O2) / Vm = 112 / 22.4 = 5 mol
nC3H8 = 5nO2
n(C3H8) = 5*1 / 5 = 1 mol
M(C3H8) =44 g/mol
m(C3H8) = n*M = 1*44 = 44 g
ответ 44 г
3)
дано
V(CO2) = 44.8 L
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m(C4H10)-?
2C4H10+13O2-->8CO2+10H2O
n(CO2) = V(CO2) / Vm = 44.8 / 22.4 = 2 mol
2nC4H10 = 8nCO2
n(C4H10) = 2*2 / 8 = 0.5 mol
M(C4H10) =58 g/mol
m(C4H10) = n*M = 0.5*58 = 29 g
ответ 29 г
4)
дано
V(O2) = 11.2 L
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m(CH4)-?
CH4+2O2-->CO2+2H2O
n(O2) = V(O2) / Vm = 11.2 / 22.4 = 0.5 mol
nCH4 = 2nO2
n(C4H10) = 1*0.5 / 2 = 0.25 mol
M(CH4) =58 g/mol
m(CH4) = n*M = 0.25*58 = 14.5 g
ответ 14.5 г
5)
дано
V(O2) = 22.4 L
------------------------
m(C6H14)-?
2C6H14+19O2-->12CO2+14H2O
n(O2) = V(O2) / Vm = 22.4 / 22.4 = 1 mol
2nC6H14 = 19nCO2
n(C6H14) = 1*2 / 19 = 0.11 mol
M(C6H14) =86 g/mol
m(C4H10) = n*M = 0.11 *86 = 9.46 g
ответ 9.46 г