дано
m(CnH2n+2OH) = 30 g
V(H2) = 5.6 L
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CnH2n+1OH - ?
2CnH2n+1OH+2Na-->2CnH2n+2ONa+H2
M(CnH2n+1OH) = (14n+18) g/mol
Vm = 22.4 L/mol
30 / 2(14n+18) = 5.6 / 22.4
30 / 28n+36 = 5.6 / 22.4
30*22.4 = 5.6(28n+36)
672 = 156.8n + 201.6
n = 3
C3H7OH
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