Упростите выражение :

Решите задачу:

$1)\frac{3}{x^{\frac{1}{3}}-y^{\frac{1}{3}}}-\frac{3}{x^{\frac{1}{3}}+y^{\frac{1}{3}}}=\frac{3x^{\frac{1}{3}}+3y^{\frac{1}{3}}-3x^{\frac{1}{3}}+3y^{\frac{1}{3}}}{(x^{\frac{1}{3}}-y^{\frac{1}{3}})(x^{\frac{1}{3}}+y^{\frac{1}{3}})}=\frac{6y^{\frac{1}{3}}}{x^{\frac{2}{3}}-y^{\frac{2}{3}}}$ $2)\frac{2x^{-\frac{2}{3}}y^{-\frac{1}{3}}}{x^{-\frac{2}{3}}-y^{-\frac{2}{3}}} =\frac{\frac{2}{x^{\frac{2}{3}}y^{\frac{1}{3}}}}{\frac{1}{x^{\frac{2}{3}}}-\frac{1}{y^{\frac{2}{3}}}}=\frac{2}{x^{\frac{2}{3}}y^{\frac{1}{3}}}*\frac{x^{\frac{2}{3}}y^{\frac{2}{3}}}{y^{\frac{2}{3}}-x^{\frac{2}{3}}}=\frac{2y^{\frac{1}{3}}}{y^{\frac{2}{3}}-x^{\frac{2}{3} }}$ $3)\frac{6y^{\frac{1}{3}}}{x^{\frac{2}{3}}-y^{\frac{2}{3}}} :\frac{2y^{\frac{1}{3}}}{y^{\frac{2}{3} }-x^{\frac{2}{3}} }=\frac{6y^{\frac{1}{3}}}{x^{\frac{2}{3}} -y^{\frac{2}{3}}}*\frac{y^{\frac{2}{3}}-x^{\frac{2}{3}}}{2y^{\frac{1}{3}}}=-3$