Помогите решить (7-2/3):(1 3/4-1/6)*(1/2+2 2/3+1/6) и по картинке

$(7 - \frac{2}{3} ) \div (1 \frac{3}{4} - \frac{1}{6} ) \times ( \frac{1}{2} + 2 \frac{2}{3} + \\ \frac{1}{6} ) = 13 \frac{1}{3}$
$1)7 - \frac{2}{3} = 6 \frac{3}{3} - \frac{2}{3} = 6 \frac{1}{3}$
2)
$1 \frac{3}{4} - \frac{1}{6} = 1 \frac{9}{12} - \frac{2}{12} = 1 \frac{7}{12}$
$3) \frac{1}{2} + 2 \frac{2}{3} + \frac{1}{6} =\frac{3}{6} + 2 \frac{4}{6} + \frac{1}{6} = \\ 2 \frac{7}{6} + \frac{1}{6} = 2 \frac{8}{6} = 3 \frac{2}{6} = 3 \frac{1}{3}$
$4)6 \frac{1}{3} \div 1 \frac{7}{12} = \frac{19}{3} \div \frac{19}{12} = \\ \frac{19}{3} \times \frac{12}{19} = 4$
$4 \times 3 \frac{1}{3} = 4 \times \frac{10}{3} = \frac{40}{3} = 13 \frac{1}{3}$