Решите систему уравнений

$\left \{ {{2x^{2} -5x=y} \atop {2x-5=y}} \right.\\\left \{ {{x(2x-5)=y} \atop {2x-5=y}} \right.\\\left \{ {{xy=y} \atop {2x-5=y}} \right.\\\left \{ {{xy-y=0} \atop {2x-5=y}} \right.\\ \left \{ {{y(x-1)=0} \atop {2x-5=y}} \right.\\\left \{ {{y=0} \atop {2x-5=0}} \right.\\ \left \{ {{y=0} \atop {x=\frac{5}{2} }} \right.\\\left \{ {{x=1} \atop {2-5=y}} \right.\\ \left \{ {{x=1} \atop {y=-3}} \right.\\(x_{1}=2,5,y_{1}=0)\\(x_{2}=1,y_{2}=-3)$

Второй способ:

2x² - 5x = 2x - 5

2x² - 7x + 5 = 0

x₁ = 2,5

x₂= 1

y₁ = 2 * 2,5 - 5 = 0

y₂ = 2 * 1 - 5 = - 3