СРОЧНО НУЖНО!! ДАЮ 50 БАЛЛОВ.

Решите задачу:

$1)\; \; x^4\cdot x\cdot x^5=x^{4+1+5}=x^{10}\\\\2)\; \; \frac{y^8\cdot y^7}{y^4}=y^{8+7-4}=y^{11}\\\\3)\; \; 36^4\cdot 6^6:6^3=\frac{6^8\cdot 6^6}{6^3}=6^{8+6-3}=6^{11}\\\\4)\; \; \frac{1,3^{12}}{1.3^4\cdot 1,3^6}=1.3^{12-4-6}=1,3^2=1,69\\\\5)\; \; \frac{(-2\frac{1}{3})^6 }{(-2\frac{1}{3})^3}=(-2\frac{1}{3})^3=(-\frac{7}{3})^3=-\frac{7^3}{3^3}=-\frac{343}{27}=-12\frac{19}{27}\\\\-\frac{(-1\frac{1}{5})^8}{(-1\frac{1}{5})^4}=-(-1\frac{1}{5})^4=(-\frac{6}{5})^4=-\frac{6^4}{5^4}=-\frac{1296}{625}=-2\frac{46}{625} =-2,0736$