(6a−10b)⋅(6a+10b)−36a в степени 2 ,если a=2 и b=0,01

Question

(6a−10b)⋅(6a+10b)−36a в степени 2 ,если a=2 и b=0,01

Answer 1

=36a²-100b²-36a²=-100b²=-100•0,0001=-0,01

Answer 2

(6a − 10b)⋅(6a + 10b) −36a² =

= 36а² - 100b² - 36a² = -100b²

при a = 2 и b = 0,01

-100b² = -100 · (0.01)² = -0.01