Только В и Г. Заранее спасибо.P. S. Задание решить уравнение.

B) $3x = \frac{4-x^{2} }{x}$

$3x = \frac{4-x^{2} }{x}$ , x≠0

$3x^{2} = 4 - x^{2}$

$3x^{2} + x^{2} = 4$

$4x^{2}=4$

$x^{2}=1$

x = ±1

x = -1, x≠0

x = 1, x≠0

x = -1

x = 1

x₁ = -1

x₂ = 1

Г) $20x^{2}+31x - 9 = 0$

$20x^{2} + 36x - 5x - 9 = 0$

$4x*(5x+9) - (5x+9) = 0$

(5x+9) * (4x-1) = 0

5x + 9 = 0

4x - 1 = 0

$x = -\frac{9}{5}$

$x = \frac{1}{4}$

x₁ = $-\frac{9}{5}$

x₂ = $\frac{1}{4}$