Решите систему неравенств {2(x+y)=46 {x^2+y^2=17^2
X+y=23 x^2+y^2=289 x=(23-y) (23-y)^2+y^2=289 529-46y+y^2+y^2=289 2y^2-46y+240=0|:2 y^2-23y+120=0 По теореме Вието y1+y2=-p=-(-23)=23 y1*y2=q=120 y1=15 y2=8 x1=23-y1=23-15 x1=8 x2=23-y2=23-8 x2=15 (8;15) и (15;8)