Решите эту дичь, даю 40 балов

=\frac{4c-3d-cd+3d}{cd}" alt="\frac{4c-3d}{cd} -\frac{c-3d}{c} =\frac{4c-3d}{cd}-\frac{d*(c-3d)}{cd}

=\frac{4c-3d-cd+3d}{cd}" align="absmiddle" class="latex-formula">=

=\frac{4-d}{d}" alt="\frac{4c-cd}{cd} =\frac{c(4-d)}{cd}

=\frac{4-d}{d}" align="absmiddle" class="latex-formula">

=\frac{(x+5)^{2}}{(x+5)(x-5) } -\frac{(x-1)(x-5)}{(x-5)(x+5)}" alt="\frac{x+5}{x-5} -\frac{x-1}{x+5}

=\frac{(x+5)^{2}}{(x+5)(x-5) } -\frac{(x-1)(x-5)}{(x-5)(x+5)}" align="absmiddle" class="latex-formula">=

$\frac{x^{2}+10 x+25}{x^{2} -25} -\frac{x^{2} -x-5x+5}{x^{2} -25}$ =

$\frac{x^{2}+10 x+25-x^{2}+6x-5 }{x^{2} -25 } =\frac{16x-20}{x^{2}-25}$

3) $x+\frac{1}{x} =\frac{x^{2} }{x} +\frac{1}{x} =\frac{x^{2} +1}{x}$

=\frac{32a^{5}*45y^{4} }{15y^{3}4a^{3} }" alt="4) \frac{32a^{5}}{15y^{3}}:\frac{4a^{3} }{45y^{4}}

=\frac{32a^{5}*45y^{4} }{15y^{3}4a^{3} }" align="absmiddle" class="latex-formula">= $\frac{8*4a^{2}*a^{3} *15*3*y^{3}*y }{15y^{3}*4a^{2} } =\frac{8*a^{2}*3y }{1} =24a^{2} y$