0\; ;\; (3x^2+5)>0\\\\znaki:\; \; +++[\, 0\, ]+++[\, 1\, ]---[\, 3\, ]+++\\\\x\in \{0\}\cup [\, 1,\, 3\, ]" alt="\frac{x^2-4x+3}{2x^2+5}\leq \frac{x^2-4x+3}{3x^2+5}\\\\\frac{x^2-4x+3}{2x^2+5}-\frac{x^2-4x+3}{3x^2+5}\leq 0\\\\\frac{(x^2-4x+3)(3x^2+5)-(x^2-4x+3)(2x^2+5)}{(2x^2+5)(3x^2+5)}\leq 0\\\\\frac{(x^2-4x+3)(3x^2+5-2x^2-5)}{(2x^2+5)(3x^2+5)}\leq 0\\\\\frac{(x^2-4x+3)\cdot x^2}{(2x^2+5)(3x^2+5)}\leq 0\; \; ,\; \; \frac{(x-1)(x-3)\cdot x^2}{(2x^2+5)(3x^2+5)}\leq 0\\\\x^2-4x+3=0\; \; \Rightarrow\; \; x_1=1\; ,\; x_2=3\; ;\; \; (2x^2+5)>0\; ;\; (3x^2+5)>0\\\\znaki:\; \; +++[\, 0\, ]+++[\, 1\, ]---[\, 3\, ]+++\\\\x\in \{0\}\cup [\, 1,\, 3\, ]" align="absmiddle" class="latex-formula">