x\\x\in (-5;5)" alt="x^2<25\\x^2-25<0\\(x-5)(x+5)<0\\+++(-5)---(5)+++>x\\x\in (-5;5)" align="absmiddle" class="latex-formula">
Ответ:
x\\x\in(-6;-4)\\" alt="x^2+10x+24<0\\y=x^2+10x+24\\y=0;\\x^2+10x+24=0\\D=100-4\cdot24=4=2^2\\x_{1,2}=\frac{-10\pm2}{2}=|{ {{-4} \atop {-6}} \right. \\+++(-6)---(-4)+++>x\\x\in(-6;-4)\\" align="absmiddle" class="latex-formula">
Ответ: