Решите уравнения различными способами.x2+6x+8=0

Решите задачу:

$1.) \\ x {}^{2} + 4x + 2x + 8 = 0 \\ x(x + 4) + 2(x + 4) = 0 \\ (x + 4)(x + 2) = 0 \\ x + 4 = 0 \\ x + 2 = 0 \\ x = - 4 \\ x = - 2 \\ 2.) \\ x {}^{2} + 6x + 8 = 0 \\ d = b {}^{2} - 4ac = 6 {}^{2} - 4 \times 8 = 36 - 32 = 4 \\ \sqrt{4 } = 2 \\ x1 = \frac{ - 6 - 2}{2} = \frac{ - 8}{2} = - 4 \\ x2 = \frac{ - 6 + 2}{2} = \frac{ - 4}{2} = - 2$