ПОМОГИТЕ РЕШИТЬ!!! Систему неравенств 1. {2x-1x-4 2. {5(x-2)-x>2 {1-3(x-1)p 6 Срочоо

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ПОМОГИТЕ РЕШИТЬ!!! Систему неравенств 1. {2x-1<1,4-x {3x-2>x-4 2. {5(x-2)-x>2 {1-3(x-1)<-2 3. 3(2-3p)-2(3-2p) >p 6 Срочоо


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imagex-4}} \right. \left \{ {{2x+x<1,4+1} \atop {3x-x>2-4}} \right. \left \{ {{3x<2,4} \atop {2x>-2}} \right.\left | {{:3} \atop {:2}} \\\left \{ {{x<0,8} \atop {x>-1}} \right. \\\left \{ {{++++++(0,8)->x} \atop {-(-1)++++++>x}} \right." alt="\displaystyle\left \{ {{2x-1<1,4-x} \atop {3x-2>x-4}} \right. \left \{ {{2x+x<1,4+1} \atop {3x-x>2-4}} \right. \left \{ {{3x<2,4} \atop {2x>-2}} \right.\left | {{:3} \atop {:2}} \\\left \{ {{x<0,8} \atop {x>-1}} \right. \\\left \{ {{++++++(0,8)->x} \atop {-(-1)++++++>x}} \right." align="absmiddle" class="latex-formula">

x\in(-1;0,8)

Ответ: (-1;0,8)


image2} \atop {1-3(x-1)<-2}} \right. \left \{ {{5x-10-x>2} \atop {1-3x+3<-2}} \right. \left \{ {{4x>12} \atop {-3x<-6}} \right. \left |{ {{:4} \atop {:(-3)}} \right. \\\\\left \{ {{x>3} \atop {x>2}} \right. \left \{ {{-------(3)++>x} \atop {-----(2)++++>x}} \right. \\x\in(3;+\infty)" alt="\displaystyle \left \{ {{5(x-2)-x>2} \atop {1-3(x-1)<-2}} \right. \left \{ {{5x-10-x>2} \atop {1-3x+3<-2}} \right. \left \{ {{4x>12} \atop {-3x<-6}} \right. \left |{ {{:4} \atop {:(-3)}} \right. \\\\\left \{ {{x>3} \atop {x>2}} \right. \left \{ {{-------(3)++>x} \atop {-----(2)++++>x}} \right. \\x\in(3;+\infty)" align="absmiddle" class="latex-formula">

Ответ: (3;+\infty)

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А можно еще решить

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3(2-3p) -2(3-2p) >p и 6