(sin2x-1)cos(x-пи/4)=0

Question

(sin2x-1)cos(x-пи/4)=0

Answer 1

(sin(2x)-1)cos(x-pi/4)=0

a)  sin(2x)-1=0

sin(2x)=1

2x=pi/2+2*pi/n

x=pi/4+pi*n

 

б)  cos(x-pi/4)=0

x-pi/4=pi/2+pi*n

x=pi/4+pi/2+pi*n

x=3*pi/4+pi*n