Найдите производную функции 1)у= tgx^3 2)y=2arctg3/x 3)y=2arcctg lnx/x
1) у= tgx³
y' = 3x²/cos²x³
2) y=2arctg3/x
y' = -2*(3/x²)/(1+(3/x)²) = -6/(x²(1+(3/x)²)
3) y=2arcctg lnx/x
y' = 2*(1/x)*(-1/x²)/(1/(lnx/x)) = -2/(x³*lnx/x)