0\\x>-\frac{1}{2}\\x+2=4x^2+4x+1\\ 4x^2+3x-1=0\\ x_{1,2}=\frac{-3±\sqrt{9-4*4*(-1)}}{8}=\frac{-3±5}{8}=\frac{1}{4};-1" alt="\sqrt{x + 2 }= 2x + 1 \\ODZ:2x+1>0\\x>-\frac{1}{2}\\x+2=4x^2+4x+1\\ 4x^2+3x-1=0\\ x_{1,2}=\frac{-3±\sqrt{9-4*4*(-1)}}{8}=\frac{-3±5}{8}=\frac{1}{4};-1" align="absmiddle" class="latex-formula">
Ответ:х=1/4