![image](https://tex.z-dn.net/?f=%5Csqrt%7Bx%20%2B%202%20%7D%3D%202x%20%2B%201%20%5C%5CODZ%3A2x%2B1%3E0%5C%5Cx%3E-%5Cfrac%7B1%7D%7B2%7D%5C%5Cx%2B2%3D4x%5E2%2B4x%2B1%5C%5C%204x%5E2%2B3x-1%3D0%5C%5C%20x_%7B1%2C2%7D%3D%5Cfrac%7B-3%C2%B1%5Csqrt%7B9-4%2A4%2A%28-1%29%7D%7D%7B8%7D%3D%5Cfrac%7B-3%C2%B15%7D%7B8%7D%3D%5Cfrac%7B1%7D%7B4%7D%3B-1)
0\\x>-\frac{1}{2}\\x+2=4x^2+4x+1\\ 4x^2+3x-1=0\\ x_{1,2}=\frac{-3±\sqrt{9-4*4*(-1)}}{8}=\frac{-3±5}{8}=\frac{1}{4};-1" alt="\sqrt{x + 2 }= 2x + 1 \\ODZ:2x+1>0\\x>-\frac{1}{2}\\x+2=4x^2+4x+1\\ 4x^2+3x-1=0\\ x_{1,2}=\frac{-3±\sqrt{9-4*4*(-1)}}{8}=\frac{-3±5}{8}=\frac{1}{4};-1" align="absmiddle" class="latex-formula">
Ответ:х=1/4