Решите систему уравнений:3x+y+4=0X^2-y^2=2
{3x+y+4=0 {x²-y²=2 {y=-3x-4 {x²-y⅜=2 x²-(-3x-4)²=2 x=-3/2 y=-3*(-3/2)-4 y=1/2 (x.y)=(-3/2,1/2) {3*(-3/2)+1/2+4=0 {(-3/2)²-(1/2)²=2 {0=0 => }2=2 (x.y)=(-3/2,1/2)