Помогите пожалуйста {x-√y=2; x^2-y=10

$\left \{ {{x-\sqrt{y}=2} \atop {x^2-y=10}} \right.\\ \\ \left \{ {{x-\sqrt{y}=2} \atop {x^2-(\sqrt{y})^2=10}} \right. \\ \\ \left \{ {{\sqrt{y} =x-2} \atop {x^2-(x-2)^2=10}} \right. \\ \\ \left \{ {{\sqrt{y} =x-2} \atop {x^2-(x^2-4x+4)=10}} \right. \\ \\ \left \{ {{\sqrt{y} =x-2} \atop {x^2-x^2+4x-4=10}} \right. \\ \\ \left \{ {{\sqrt{y} =x-2} \atop {4x=14}} \right. \\ \\ \left \{ {{\sqrt{y} =\frac{7}{2}-2} \atop {x=\frac{7}{2}}} \right.$

$\left \{ {{\sqrt{y}=1.5} \atop {x=\frac{7}{2}}} \right. \\ \\ \left \{ {{y=2.25} \atop {x=\frac{7}{2}}} \right.$

Ответ: (7/2; 2.25)