Решите уравнение под номером 811!! Пожалуйста!!

Решите задачу:

$1) \frac{7(x - 6)}{4} + \frac{5(x + 1)}{3} - 3(x + 2) \\ \frac{7x - 42}{4} + \frac{5x + 5}{3} - 3x - 6 \\ \frac{3(7x - 42) + 4(5x + 5) - 36x - 72}{12} \\ \frac{21x - 126 + 20x + 20 - 36x - 72}{12} \\ \frac{5x - 178}{12} \\ 2) \frac{3(x - 8)}{5} + \frac{7(x + 5)}{6} = \frac{4(7x + 1.5)}{15} + \frac{1}{3} \\ \frac{3x - 24}{5} + \frac{7x + 35}{6} = \frac{28x + 6}{15} + \frac{1}{3} \\ 6(3x - 24) + 5(7x + 35) = 2(28x + 6) + 10 \\ 18x - 144 + 35x + 175 = 56x + 12 + 10 \\ 53x + 31 = 56x + 22 \\ 56x - 56x = 22 - 31 \\ - 3x = - 9 \\ x = 3 \\ 3) \frac{3(2x + 5)}{8} - \frac{2(5x + 7)}{ 3} = \frac{7(x - 15)}{4} - \frac{55}{8} \\ \frac{6x + 5}{8} - \frac{10x + 14}{3} = \frac{7x105}{4} - \frac{55}{8} \\ 3(6x + 15) - 8(10x + 14) = 6(7x - 105) - 165 \\ 18x + 45 - 80x - 112 = 42x - 630 - 165 \\ - 62x - 67 = 42x - 795 \\ - 62x - 42x = - 795 + 67 \\ - 104x = - 728 \\ x = 7$