Номер 60 Заранее спасибо)))

Решите задачу:

$1) \frac{2 - \frac{1}{ \frac{3}{4} } }{2 + \frac{1}{ \frac{3}{4} } } = \frac{2 - \frac{4}{3} }{2 + \frac{4}{3} } = \frac{ \frac{2}{3} }{ \frac{10}{3} } = \frac{2}{10} = \frac{1}{5} = 0.2 \\ 2) \frac{4 + \frac{1}{ \frac{1}{6} } }{4 - \frac{1}{ \frac{1}{6} } } = \frac{4 + 6}{4 - 6} = \frac{10}{ - 2} = - 5 \\ 3)1 - \frac{1}{ \frac{3}{2} } = 1 - \frac{2}{3} = \frac{1}{3} = 0.3 \\ 4)2 \frac{2}{ \frac{1}{3} } = 2 + 6 = 8 \\ 5)1 + \frac{1}{1 + \frac{1}{ \frac{3}{2} } } = 1 + \frac{1}{1 + \frac{2}{3} } = 1 + \frac{1}{ \frac{5}{3} } = 1 + \frac{3}{5} = \frac{8}{5} = 1 \frac{3}{5} = 1.6 \\ 6)3 - \frac{3}{3 - \frac{1}{ \frac{2}{3} } } = 3 - \frac{3}{3 - \frac{3}{2} } = 3 - \frac{3}{ \frac{3}{2} } = 3 - 2 = 1$