дано
m(Mg) = 6 g
----------------------
V(H2)-?
Mg+2CH3COOH--->(CH3COO)2Mg+H2
M(Mg) = 24 g/mol
n(Mg) = m/M = 6/ 24 = 0.25 mol
n(Mg) = n(H2) = 0.25 mol
V(H2) = n*Vm = 0.25 * 22.4 = 5.6 L
ответ 5.6 л
дано
m(ppa CH3COOH) = 150 g
W(CH3COOH) = 10 %
-----------------------------------
m(NaOH)-?
m(CH3COOH) = 150 * 10% / 100% = 15 g
CH3COOH+NaOH--->CH3COONa+H2O
M(CH3COOH) = 60 g/mol
n(CH3COOH) = m/M = 15 / 60 = 0.25 mol
n(CH3COOH) = n(NaOH) = 0.25 mol
M(NaOH) = 40 g/mol
m(NaOH) = n*M = 0.25 * 40 = 10 g
ответ 10 г