Решите пожалуйста очень срочно!!!!

Решите задачу:

$1)\sqrt{\sqrt{20}-2 } *\sqrt{\sqrt{20}+2 }=\sqrt{(\sqrt{20}-2)(\sqrt{20}+2)}=\sqrt{(\sqrt{20)^{2}}-2^{2}}=\sqrt{20-4}=\sqrt{16}=4\\\\2)(\sqrt{11+6\sqrt{2} }-\sqrt{11-6\sqrt{2} })^{2} =(\sqrt{11+6\sqrt{2} })^{2}-2*\sqrt{11+6\sqrt{2} }*\sqrt{11-6\sqrt{2} }+(\sqrt{11-6\sqrt{2} })^{2}=11+6\sqrt{2}-2*\sqrt{(11-6\sqrt{2})(11+6\sqrt{2}}+11-6\sqrt{2}=22-2*\sqrt{11^{2} -(6\sqrt{2})^{2}}=22-2*\sqrt{121-72}=22-2*\sqrt{49} =22-2*7=8$