Помогите пожалуйста!!!

Ответ:

2) x = 2

3) x = -22, x = 32

Пошаговое объяснение:

$2.\\\\ \frac{x+2}{3} - 1 = \frac{x+6}{12}-\frac{x}{6}\\\\\frac{x}{3}+\frac{2}{3}-1 = \frac{x}{12} + \frac{6}{12} - \frac{x}{6}\\\\\frac{x}{3} - \frac{x}{12} + \frac{x}{6} = 1-\frac{2}{3}+\frac{6}{12}\\\\\frac{4x-x+2x}{12} = \frac{1}{3} + \frac{1}{2}\\\\\frac{5x}{12} = \frac{5}{6}\\\\5x = \frac{12\cdot 5}{6}\\\\5x = 10\\x = 2$

$3.\\\\6|x-5| = 162\\\\|x-5| = 27 \Leftrightarrow \left [\begin{array}{lcl} {{x-5=27, \;\;x \geq 5} \\ {x-5=-27, \; x < 5}}\end{array} \right. \Leftrightarrow \left [\begin{array}{lcl} {{x=32} \\ {x=-22}}\end{array} \right.$