Решите ПОЖАЛУЙСТА уравнение!! СРОЧНО!!!

$\frac{5}{x^{2}+2x+1 } =\frac{2}{1-x^{2} }+\frac{1}{x-1}\\\\\frac{5}{(x+1)^{2} }+\frac{2}{(x-1)(x+1)}-\frac{1}{x-1}=0\\\\\frac{5(x-1)+2(x+1)-1(x^{2}+2x+1)}{(x+1)^{2}(x-1) }=0\\\\\frac{5x-5+2x+2-x^{2}-2x-1 }{(x+1)^{2}(x-1) }=0\\\\\frac{-x^{2}+5x-4 }{(x+1)^{2}(x-1) }=0\\\\x^{2} -5x+4=0\\\\D=(-5)^{2}-4*4=25-16=9=3^{2}\\\\x_{1}=\frac{5+3}{2}=4\\\\x_{2}=\frac{5-3}{2}=1\\\\x-1\neq0\\\\x\neq1\\\\x+1\neq0\\\\x\neq-1$

Ответ : 4