30 баллов! Алгебра 10-11 класс! Срочно!

$1)\sqrt{9-2\sqrt{14}}+\frac{5}{\sqrt[3]{(\sqrt{2}-\sqrt{7})^3}}=$

$=\sqrt{7-2\sqrt{14}+2}+\frac{5}{(\sqrt{2}-\sqrt{7})}=$

$=\sqrt{(\sqrt{7})^2-2\sqrt{7}*\sqrt{2}+(\sqrt{2})^2}+\frac{5}{(\sqrt{2}-\sqrt{7})}=$

$=\sqrt{(\sqrt{7}-\sqrt{2})^2}+\frac{5}{(\sqrt{2}-\sqrt{7})}=$

$=\sqrt{7}-\sqrt{2}+\frac{5}{\sqrt{2}-\sqrt{7}}=$

$=\sqrt{7}-\sqrt{2}+\frac{5*(\sqrt{2}+\sqrt{7})}{(\sqrt{2}-\sqrt{7})*(\sqrt{2}+\sqrt{7}))}=$

$=\sqrt{7}-\sqrt{2}+\frac{5*(\sqrt{2}+\sqrt{7})}{(\sqrt{2})^2-(\sqrt{7})^2}=$

$=\sqrt{7}-\sqrt{2}+\frac{5*(\sqrt{2}+\sqrt{7})}{2-7}=$

$=\sqrt{7}-\sqrt{2}+\frac{5*(\sqrt{2}+\sqrt{7})}{-5}=$

$=\sqrt{7}-\sqrt{2}-\sqrt{2}-\sqrt{7}=$

$=-2\sqrt{2}=$

2) 25% = ²⁵/₁₀₀ = 0,25

$3)-2\sqrt{2}:0,25=-8\sqrt{2}$

Ответ: -8√2