Сделаем замену :
0\\\\3^{y}=b,b>0\\\\\left \{ {{3a+2b=12} \atop {a-b=-1}|*2} \right.\\\\+\left \{ {{3a+2b=12} \atop {2a-2b=-2}} \right\\\\--------\\\\5a=10\\\\a=2\\\\b=a+1=2+1=3\\\\2^{x}=2\\\\x=1\\\\3^{y}=3\\\\y=1" alt="2^{x} =a,a>0\\\\3^{y}=b,b>0\\\\\left \{ {{3a+2b=12} \atop {a-b=-1}|*2} \right.\\\\+\left \{ {{3a+2b=12} \atop {2a-2b=-2}} \right\\\\--------\\\\5a=10\\\\a=2\\\\b=a+1=2+1=3\\\\2^{x}=2\\\\x=1\\\\3^{y}=3\\\\y=1" align="absmiddle" class="latex-formula">
Ответ : (1 ; 1)