1. (447 div 3) mod 72. (384 mod 2) mod 33. 587 div 10 mod 10

Question

1. (447 div 3) mod 72. (384 mod 2) mod 33. 587 div 10 mod 10

Answer 1

(447 div 3) mod 7 = 2

(384 mod 2) mod 3 = 0

587 div 10 mod 10 = 8