Решите систему уравнений 2х^2у-у=7 ху-х+3у-3=0

$\left \{ {{2x^2y-y=7} \atop {xy-x+3y-3=0}} \right$

$\left \{ {{2x^2y-y=7} \atop {(y-1)(x+3) = 0}} \right$

$\left [ {{ \left \{ {{2x^2y-y=7} \atop {x = -3}} \right \atop \left \{ {{2x^2y-y=7} \atop { y = 1}} \right \right$

$\left [ {{ \left \{ {{2*9y-y=7} \atop {x = -3}} \right \atop \left \{ {{2x^2-1=7} \atop { y = 1}} \right \right$

$\left [ {{ \left \{ {{y=7/17} \atop {x = -3}} \right \atop \left \{ {{x =\pm 2} \atop { y = 1}} \right \right$

Ответ: (-3, 7/17), (-2, 1), (2, 1)