Sin3α+sai5α= cos4α-cos2α= sin6α-sin2α= cos7α+cosα=

Question

Sin3α+sai5α= cos4α-cos2α= sin6α-sin2α= cos7α+cosα=

Answer 1

Sin3a + sai5a = (3ans + 5a `2 s) i
*(2 как степень)

cos4a - cos2a = 2 a c o s

sin6a - sin2a = 4 a n s i

cos7a + cosa = 8 a c o s