Помогите с дз. Дам 21 баллов! Не пишите чушь.

1) $\frac{y-2}{y-5}+\frac{y+2}{2y+1}=\frac{(y-2)(y+2)}{(y-5)(2y+1)};\\ \frac{(y-2)(2y+1)+(y+2)(y-5)}{(y-5)(2y+1)}-\frac{(y-2)(y+2)}{(y-5)(2y+1)}=0;\\\frac{2y^2+y-4y-2+y^2+2y-5y-10-y^2-4}{(y-5)(2y+1)}=0;\\\frac{(2+1-1)y^2+(1-4+2-5)y+(-2-10-4)}{(y-5)(2y+1)} =0;\\$

$\frac{1y^2-3y-8}{(y-5)(2y+1)}=0;D=9+32=41\\ y=\frac{3б\sqrt{41} }{2}$ Ответ.

2) $\frac{2y-23}{y+3} -\frac{y+1}{y-7} = \frac{(2y-23)(y+1)}{(y+3)(y-7)} ;\\\frac{(2y-23)(y-7)-(y+1)(y+3)-(2y-23)(y+1)}{(y+3)(y-7)}=0;\\\frac{(2y-23)(y-7-(y+1))-(y+1)(y+3)}{(y+3)(y-7)}=0;\\\frac{-12y+138-y^2-4y-3}{(y+3)(y-7)}=0;\\\frac{y^2+16y-135}{(y+3)(y-7)}=0;D=256+540= 796;$

$y=\frac{-16б2\sqrt{199} }{2} =-8б\sqrt{199}$ Ответ.