Химия срочно даю 50б

Question

Химия срочно даю 50б

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Answer 1

CH3-CH2-CH3+5O2=3CO2+4H2O

CH3-C(CH3)(CH3)-Br+2K+Br-CH3-> CH3-C(CH3)(CH3)-CH3+2KBr

CH3-CH=CH2+H2-> CH3-CH2-CH3