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Решите задачу:

$\frac{\sqrt{648}}{18}=\sqrt{2}$

$\frac{\sqrt{675}}{15}=\sqrt{3}$

$\frac{\sqrt{875}}{5}=\sqrt{35}$

$\frac{\sqrt{216}}{6}=\sqrt{6}$

$\frac{\sqrt{98}}{7}=\sqrt{2}$

$\frac{\sqrt{432}}{12}=\sqrt{3}$

$\frac{\sqrt{726}}{11}=\sqrt{6}$

$\frac{\sqrt{675}}{15}=\sqrt{3}$

$\frac{\sqrt{875}}{5}=\sqrt{35}$

$2^{12} *(2^{3})^{-5} =2^{12}*2^{-15}=2^{-3}=1/8=0,125$

$3^{-9} *(3^{4})^{3} =3^{-9}*3^{12}=3^{3}=27$

$\frac{\sqrt{512}}{8}=\sqrt{8}=2\sqrt{2}$

$\frac{\sqrt{98}}{7}=\sqrt{2}$

$\frac{\sqrt{432}}{12}=\sqrt{3}$

$\frac{\sqrt{726}}{11}=\sqrt{6}$