Помогите кто чем может срочно

a)\frac{1}{2} \\log_{16}(4x+3)>log_{16}(-4)\\4x+3>-4\\x>-\frac{7}{4}" alt="log_{16}(4x+3)>\frac{1}{2} \\log_{16}(4x+3)>log_{16}(-4)\\4x+3>-4\\x>-\frac{7}{4}" align="absmiddle" class="latex-formula">

б) $log_{\frac{1}{4}}(4x+3)\geq - 1\\log_{\frac{1}{4}}(4x+3)\geq log_{\frac{1}{4}}4\\4x+3\geq 4\\x\geq \frac{1}{4}$

в) $log^{2}_{4}x-log_{4}x-6<0\\(log_{4}x-3)(log_{4}x+2)<0\\$

0}} \right.\\\left \{ {{log_{4}x<3} \atop {log_{4}x>-2}} \right. \\\left \{ {{log_{4}xlog_{4}\frac{1}{16} }} \right. \\\left \{ {{x<64} \atop {x>\frac{1}{16} }} \right. \\(1/16 ; 64)" alt="\left \{ {{log_{4}x-3<0} \atop {log_{4}x+2>0}} \right.\\\left \{ {{log_{4}x<3} \atop {log_{4}x>-2}} \right. \\\left \{ {{log_{4}xlog_{4}\frac{1}{16} }} \right. \\\left \{ {{x<64} \atop {x>\frac{1}{16} }} \right. \\(1/16 ; 64)" align="absmiddle" class="latex-formula">

г) log_{2}(2-7x)\\3x-1>2-7x\\10x>3\\x>\frac{3}{10}" alt="log_{2}(3x-1)>log_{2}(2-7x)\\3x-1>2-7x\\10x>3\\x>\frac{3}{10}" align="absmiddle" class="latex-formula">