Решите пж 34.8 и 34.9

Решите задачу:

$34.8.1) (1-4x)(1+4x+16x^2)-6x^3\leq10x-70x^3\\1-64x^3-6x^3\leq10x-70x^3\\1\leq10x\\x\geq\frac{1}{10}\\34.8.2) 99x^3-(1+5x)(1-5x+25x^2)\geq12x-26x^3\\99x^3-(1+125x^3)\geq12x-26x^3\\-1\geq12x\\x\leq-\frac{1}{12}$

$34.9.1) (5x-6)(25x^2+30x+36)-0,25(500x^3-864)=125x^3-216-125x^3+216=0\\34.9.2) 91x^3-(3x-4)(9x^2+12x+16)-(3+4x)(9-12x+16x^2)=91x^3-(27x^3-64)-(64x^3+27)=64-27=37$